A compound forms hexagonal close-packed structure Chapter 1: the Solid State Chemistry Class 12 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 1.15: A compound forms hexagonal close−packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids? is solved by our expert teachers. You can get ncert solutions and notes for class 12 chapter 1 absolutely free. NCERT Solutions for class 12 Chemistry Chapter 1: the Solid State is very essencial for getting good marks in CBSE Board examinations

Question 1.15: A compound forms hexagonal close−packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids?

Answer
Number of atoms in close packaging = 0.5 mol
1 has 6.022 ×10²³ particles
So that
Number of close−packed particles
= 0.5 × 6.022 × 10²³ = 3.011 × 10²³
Number of tetrahedral voids = 2 × number of atoms in close packaging
Plug the values we get
Number of tetrahedral voids = 2 × 3.011 × 10²³
                                        = 6.022 × 10²³
Number of octahedral voids = number of atoms in close packaging
So that
Number of octahedral voids = 3.011 × 10²³
Total number of voids = Tetrahedral void + octahedral void
                                     = 6.022 × 10²³ + 3.011 × 10²³
                                       = 9.03 × 10²³

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